Let's begin by assuming a circular orbit of a test particle around a planetesimal of relative mass much greater than the mass of the test particle in question (m << M). From Kepler's Third Law the orbital period of the test particle is given by:
We define the Hill radius as the distance from where the orbital period of the test particle around the planetesimal is equal to the orbital period of the planetesimal around the Sun. Suppose at a distance d, the orbital period of the planetesimal around the sun is equal to the orbital period of the test particle around the planetesimal.
Setting their orbital periods equal gives:
Doing a bit of algebra we then have the Hill Radius as:
Rewritten with term alpha,
Where term alpha is defined by the planetesimal and sun's mass-densities:
In applications, the Hill Sphere describes the gravitational sphere of influence of a planetesimal in a multiple body system such as the two-body system of the Sun and Earth. Supposing a particle comes within the vicinity of a two-body system with one larger and one smaller object in relative masses. If the particle passes through the Hill sphere of the smaller object with a relatively low velocity, the particle will then be tied to the smaller not larger object's orbit. The continual collection of particles by an object will cause the object's radius to grow as well as its Hill radius.
Calculating Earth's Hill Radius
The Earth and Sun have mass densities:
The radius of the Sun and Earth's distance to the sun:
This means if an object came within .01 AU of the Earth at a relatively low velocity it would become caught within Earth's orbit and not the Sun's orbit.
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In this diagram the Hill Sphere's are denoted by the circular regions surrounding the Earth and Sun. |
Sources: Wikipedia: Nebular Theory, Hill Sphere, Orbital Period
Carroll: The Hill Radius
Hill spheres, very interesting! Never knew about them before now. Great post!
ReplyDeleteThanks for the post Mad Physi, I actually found an error in my calculation of the Hill Radius of the Earth. I incorrectly calculated the masses of both the Earth and Sun by density. If I used the masses given by wikipedia in the equation http://i.imgur.com/M4Raj.gif instead I would have gotten a more accurate number for the radius.
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